Pergunta complicada do JEE Main 2023 | 98% não conseguiram resolver isso #shorts #jee #jee2023 #jeemains

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48 comentários em “Pergunta complicada do JEE Main 2023 | 98% não conseguiram resolver isso #shorts #jee #jee2023 #jeemains”

  1. Another method:
    2023^2023 = (1995 + 28)^2023 = 1995q + 28^2023
    Now as 1995q is divisible by 35 for q be an integer, 28^2023 can be written as :
    (35-7)^2023 = 35Q – 7^2023 where Q is an integer then 35Q is divisible by 35, so -7^2023 can be written as:
    -7(7^2)^1011 = -7(50-1)^1011 = -7(50P – 1^1011) where P is an integer. Now,
    = -350P + 7…. So again as 350 is divisible by 35, 7 is the remainder…
    Thanks

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